There are two conditions to determining limits by inspection
1. x goes to positive or negative infinity
2. limit involves a polynomial divided by a polynomial
Example:
lim (x3 - 4)/(x2 +x+1)
This problem on two conditions:
1. polynomial over polynomial
2. x approaches infinity
If the highest power of x is greater in numerator so the limit is positive or negative infinity
Example:
1. lim (x3 - 4)/(x2 +x+1)
- Highest power of x in numerator is 3
- Highest power of x in denominator is 2
Since all the number are positive and x going to positive infinity so value the limit is infinity.
lim (x3 - 4)/(x2 +x+1) = infinity
If you can’t tell if the answer is positive or negative infinity:
Ø You can substitute a large number for x
Ø See if you end up with a positive or negative number
Ø Whatever sign you get is the sign of infinity for the limit
2. lim (x3 - 4)/(x4 +3x+5)
- Highest power of x in numerator is 3
- Highest power of x in denominator is 4
lim (x3 - 4)/(x4 +3x+5)
= ((x3-4)/x4)/(x4+3x+5)/x4)
= 0
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